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An ice-cube of density $900 \mathrm{~kg} / \mathrm{m}^3$ is floating in water of density $1000 \mathrm{~kg} / \mathrm{m}^3$. The percentage of volume of ice-cube outside the water is
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$10 \%$
The percentage of volume of ice cube outside the water is
$\begin{aligned} & =\frac{p_{\text {water }}-p_{\text {ice }}}{p_{\text {water }}} \times 100 \\ & =\frac{1000-900}{1000} \times 100=10 \%\end{aligned}$
$\begin{aligned} & =\frac{p_{\text {water }}-p_{\text {ice }}}{p_{\text {water }}} \times 100 \\ & =\frac{1000-900}{1000} \times 100=10 \%\end{aligned}$
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