An ideal coil of 10 H is connected in series with a resistance of 5 Ω and a battery of 5 V . 2 seconds after the connection is made, the current flowing in ampere in the circuit is

Question

An ideal coil of 10 H is connected in series with a resistance of 5 Ω and a battery of 5 V . 2 seconds after the connection is made, the current flowing in ampere in the circuit is, 1 - e -1, 1 - e, e, e -1

MARKS App · Accepted Answer

During the growth of current in LR circuit is given by I = I 0 1 - e - R L t or I = E R 1 - e - R L t = 5 5 1 - e - 5 10 × 2 I = 1 - e -1 .

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