Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
An inclined plane is located at angle α=53° to the horizontal. There is a hole at point B in the inclined plane as shown in the figure. A particle is projected along the plane with speed v0 at an angle β=37° to the horizontal in such a way so that it gets into the hole. Neglect any type of friction. Find the speed v0 (in m s-1) if h=1 m and l=8m.

PhysicsMotion In Two DimensionsJEE Main
Options:
  • A 9
  • B 3
  • C 6
  • D 12
Solution:
2187 Upvotes Verified Answer
The correct answer is: 9


h=ltanβ-12gsinαl2v02cos2β
v0=gsinαl22cos2βltanβ-h
=10×45×8×82×45×458×34-1=9 m s-1

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.