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Question: Answered & Verified by Expert
An ion with mass number 56 contains 3 units of positive charge and \(\mathbf{3 0 . 4} \%\) more neutrons than electrons. Assign the symbol to this ion.
ChemistryStructure of Atom
Solution:
1847 Upvotes Verified Answer
Suppose number of electrons in the ion, \(\mathrm{M}^{3+}=\mathrm{x}\)
\(\therefore \quad\) No. of neutrons \(=x+\frac{30.4}{100} x=1.304 x\)
No. of electrons in the neutral atom \(=x+3\)
\(\therefore\) No. of protons \(=\mathrm{x}+3\)
Mass no, \(=\) No. of protons \(+\) No. of neutrons
\(56=x+3+1.304 x\) or \(2.304 x=53\) or \(x=23\)
\(\therefore\) No. of protons \(=\) Atomic no. \(=x+3=23+3=26\)
Hence, the symbol of the ion will be \({ }_{26}^{56} \mathrm{Fe}^{3+}\).

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