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Question: Answered & Verified by Expert
An object of mass 8 kg starts to move from rest under the action of a variable force F=3x N where x is the distance (in m) covered by the object. If initially, the position of the object is x=2 m, then find its speed (in m s-1) when it crosses x=10 m.
PhysicsWork Power EnergyJEE Main
Solution:
1381 Upvotes Verified Answer
The correct answer is: 6

Increment in kinetic energy = work done

12mv2-u2=x1x2F.dx=2103x dx

12mv2=32x2210=32100-4

12×8×v2=32×96

v=6 m s-1

 

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