${\mathrm{C}}_6{\mathrm{H}}_6{\mathrm{Br}}_2$:-

Double bond equivalent formula = $\mathrm{C}-\frac{\mathrm{H}}{2}-\frac{\mathrm{X}}{2}+1$

$\mathrm{C}=6; \mathrm{H}=6;\mathrm{X}=2$

$\mathrm{DBU}=6-\frac{6}{2}-\frac{2}{2}+1=6-4+1=3$

So, it has one ring with two double bonds. It has the two bromo groups at the $1,4$ position and has the six membered carbon ring with non-conjugated double bond.

Hence, the structure of compound is :-

.

Hence, the above compound is homo-cyclic but not aromatic.