An α -paticle approaches the target nucleus of copper (Z = 29) in such a way that the value of impact parameter is zero. The distance of closest approach will be

Question

An α -paticle approaches the target nucleus of copper (Z = 29) in such a way that the value of impact parameter is zero. The distance of closest approach will be, 2 π ε 0 ( K . E . ) α 29 e 2, 29 e 2 2 π ε 0 ( K . E . ) α, 4 π ε 0 ( K . E . ) α 29 e 2, ( K . E . ) α

MARKS App · Accepted Answer

Distance of closest approach K q 1 q 2 r = ( K . E . ) α K = 1 4 π ε 0 1 4 π ε 0 Z e × 2 e r = ( K . E . ) α 1 4 π ε 0 2 × 29 e 2 r = ( K . E . ) α r = 1 2 π ε 0 × 29 e 2 ( K . E . ) α

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