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Question: Answered & Verified by Expert
An unknown compound A dissociates at 500°C to give products as follows –
A(g)B(g)+C(g)+D(g)
Vapour density of the equilibrium mixture is 50 when it dissociates to the extent to 10% . What will be the molecular weight of Compound A–
ChemistryChemical EquilibriumNEET
Options:
  • A 120
  • B 130
  • C 134
  • D 140
Solution:
1254 Upvotes Verified Answer
The correct answer is: 120
A g B g +C g +D g
α= Iintial vapour densityVapour density at equilibrium moles of gaseous product×vapour density at equilbrium
1 10 = Vapour density50 31 50
Vapour density=60
Molar mass of  compound A=2×VD=2×60=120 gm/mol

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