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Question: Answered & Verified by Expert
Angle between the tangents to the circle $x^2+y^2=25 x^2$ from the point $(1,7)$ is
MathematicsCircleMHT CETMHT CET 2022 (07 Aug Shift 2)
Options:
  • A $\frac{\pi}{4}$
  • B $\tan ^{-1}\left(\frac{2}{5}\right)$
  • C $\tan ^{-1} 2$
  • D $\frac{\pi}{2}$
Solution:
1535 Upvotes Verified Answer
The correct answer is: $\frac{\pi}{2}$

$\begin{aligned} & \mathrm{OP}=5 \sqrt{2} \\ & \mathrm{OT}=5 \\ & \mathrm{PT}=\sqrt{\mathrm{OP}^2-\mathrm{OT}^2}=5 \\ & \Rightarrow \angle \mathrm{OPT}=45^{\circ} \\ & \Rightarrow \angle \mathrm{TPT}^{\prime}=2 \angle \mathrm{OPT}=2 \times 45^{\circ}=90^{\circ}\end{aligned}$

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