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Aqueous solution of a salt $(A)$ forms a dense white precipitate with $\mathrm{BaCl}_{2}$ solution. The precipitate dissolves in dilute $\mathrm{HCl}$ to produce a gas $(B)$ which decolourises acidified $\mathrm{KMnO}_{4}$ solution.
$A$ and $B$ respectively are
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$A$ and $B$ respectively are
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The correct answer is:
$\mathrm{BaSO}_{3}, \mathrm{SO}_{2}$
$\mathrm{BaSO}_{3}(a q)+\mathrm{BaCl}_{2}(a q) \longrightarrow \mathrm{BaSO}_{4}+$ other product dense white percipitate $\mathrm{BaSO}_{4}+\mathrm{HCl} \longrightarrow \mathrm{SO}_{2}(g)+$ other product white ppt. We know that, $\mathrm{KMnO}_{4}$ can be decoloured by gas $\mathrm{SO}_{2}$. So, $A$ will be $\mathrm{BaSO}_{3}$ and $B$ will be $\mathrm{SO}_{2}$.
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