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Area bounded by the curve $y=x^{3}$, the $X$-axis and the ordinates at $x=-2$ and $x=1$, is
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$\frac{17}{4}$ sq units
$\begin{aligned} \text { Required area } &=\left|\int_{-2}^{0} x^{3} d x\right|+\int_{0}^{1} x^{3} d x \\ &=\left|\left[\frac{x^{4}}{4}\right]_{-2}^{0}\right|+\left[\frac{x^{4}}{4}\right]_{0}^{1}=\frac{16}{4}+\frac{1}{4}=\frac{17}{4} \text { squnits } \end{aligned}$
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