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Area bounded by the lines $y=x, x=-1, x=2$ and $x$-axis is
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$\frac{5}{2}$ sq. unit
Required area $\int_{-1}^2 y d x=\int_{-1}^0 y \cdot d x+\int_0^2 y . d x=\frac{5}{2}$ sq. unit.
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