Search any question & find its solution
Question:
Answered & Verified by Expert
Area bounded by $y=x \sin x$ and $x$ - axis between $x=0$ and $x=2 \pi$, is
Options:
Solution:
2476 Upvotes
Verified Answer
The correct answer is:
$4 \pi$ sq. unit
Required area is
$A_1+A_2=\int_0^\pi y d x+\left|\int_\pi^{2 \pi} y d x\right|=4 \pi \text { sq.unit }$
$A_1+A_2=\int_0^\pi y d x+\left|\int_\pi^{2 \pi} y d x\right|=4 \pi \text { sq.unit }$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.