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Arrange the following bromides in the order of reactivity in undergoing $\mathrm{S}_{\mathrm{N}} 1$ reaction.
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The correct answer is:
i $>$ iii $>$ ii $>$ iv
As stability of carbocation is in order $\rightarrow 3^{\circ}>20>1^{\circ}$, so the order of $S_N 1$ reaction in alkyl halide.
(i) $3^{\circ}>2^{\circ}>1^{\circ}$
So, the correct order is $i i i>i i>i v$.
(i) $3^{\circ}>2^{\circ}>1^{\circ}$
So, the correct order is $i i i>i i>i v$.
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