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Arrange the following hydrogen halides in order of their decreasing reactivity with propene.
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The correct answer is:
$\mathrm{HI}>\mathrm{HBr}>\mathrm{HCl}$
$\mathrm{HI}>\mathrm{HBr}>\mathrm{HCl}$
Lesser the bond energy of hydrogen halide more will be its reactivity. Hence, the order of reactivity of given compounds with propene will be $\mathrm{HI}>\mathrm{HBr}>\mathrm{HCl}$.
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