Search any question & find its solution
Question:
Answered & Verified by Expert
Arrange the following in increasing order of their intermolecular forces:
Nylon -6,6 (I), Buna –S (II), Polythene (III)
Options:
Nylon -6,6 (I), Buna –S (II), Polythene (III)
Solution:
1549 Upvotes
Verified Answer
The correct answer is:
II, III, I
Nylon- 6, 6 are fibres and these are polymers which have strong intermolecular forces such as hydrogen bonding. Buna- S is an elastomer and has weak intermolecular forces. Polyethylene are thermoplastics in which intermolecular forces of attraction are neither very strong nor very weak. Based on it the correct order is I > III > II.
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.