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Question:
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Arrange the following in order of increasing mass
I. 1 mole of \(\mathrm{N}_2\)
II. \(0.5 \mathrm{~mole}^2\) of \(\mathrm{O}_3\)
III. \(3.011 \times 10^{23} \mathrm{molecules}\) of \(\mathrm{O}_2\)
IV. 0.5 gram atom of \(\mathrm{O}_2\)
Options:
I. 1 mole of \(\mathrm{N}_2\)
II. \(0.5 \mathrm{~mole}^2\) of \(\mathrm{O}_3\)
III. \(3.011 \times 10^{23} \mathrm{molecules}\) of \(\mathrm{O}_2\)
IV. 0.5 gram atom of \(\mathrm{O}_2\)
Solution:
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Verified Answer
The correct answer is:
IV \( < \) III \( < \) II \( < \) I
Hint : 1 mole \(\mathrm{N}_2=28 \mathrm{~g}\)
\(0.5 \mathrm{~mole} \mathrm{O}_3=24 \mathrm{~g}\)
\(3.011 \times 10^{23}\) molecules of \(\mathrm{O}_2=1 / 2\) mole \(\mathrm{O}_2=1\) mole \(\mathrm{O}=16 \mathrm{~g}\)
\(0.5 \mathrm{~g}\) atom \(\mathrm{O}_2=1 / 2\) mole of atoms of \(\mathrm{O}=8 \mathrm{~g}\)
\(0.5 \mathrm{~mole} \mathrm{O}_3=24 \mathrm{~g}\)
\(3.011 \times 10^{23}\) molecules of \(\mathrm{O}_2=1 / 2\) mole \(\mathrm{O}_2=1\) mole \(\mathrm{O}=16 \mathrm{~g}\)
\(0.5 \mathrm{~g}\) atom \(\mathrm{O}_2=1 / 2\) mole of atoms of \(\mathrm{O}=8 \mathrm{~g}\)
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