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Arrange the oxides $\mathrm{CrO}, \mathrm{CrO}_3$ and $\mathrm{Cr}_2 \mathrm{O}_3$ in the decreasing order of acidic strength
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The correct answer is:
$\mathrm{CrO}_3>\mathrm{Cr}_2 \mathrm{O}_3>\mathrm{CrO}$
$\mathrm{Cr}$ in higher oxidation state will be more acidic. Thus, the order of acidic strength will be :-
$\stackrel{+6}{\mathrm{CrO}_3}>\stackrel{+3}{\mathrm{CrO}} \mathrm{O}_3>\stackrel{+2}{\mathrm{Cr} O}$
$\stackrel{+6}{\mathrm{CrO}_3}>\stackrel{+3}{\mathrm{CrO}} \mathrm{O}_3>\stackrel{+2}{\mathrm{Cr} O}$
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