Sodium acetate $\left({\mathrm{CH}}_3\mathrm{COONa}\right)$ on Kolbe's electrolysis gives ethane $\left({\mathrm{C}}_2{\mathrm{H}}_6\right)$. The sodium acetate dissociates as -

${\mathrm{CH}}_3\mathrm{COONa}\rightleftharpoons {\mathrm{CH}}_3{\mathrm{COO}}^{-}+{\mathrm{Na}}^{+}$

At anode:

$2{\mathrm{CH}}_3{\mathrm{COO}}^{-}\stackrel{-2{\mathrm{e}}^{-}}{\to }2{\mathrm{CH}}_3{\mathrm{COO}}^{\bullet }\to 2{{\mathrm{CH}}_3}^{\bullet }+2{\mathrm{CO}}_2\uparrow$

${\mathrm{H}}_3{\mathrm{C}}^{\bullet }+{}^{\bullet }{\mathrm{CH}}_3\to {\mathrm{CH}}_3-{\mathrm{CH}}_3\uparrow$

At cathode:

${\mathrm{H}}_2\mathrm{O}+{\mathrm{e}}^{-}{\to }^{-}\mathrm{OH}+{\mathrm{H}}^{\bullet }$

$2{\mathrm{H}}^{\bullet }\to {\mathrm{H}}_2$