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Assertion: $\mathrm{Sb}_2 \mathrm{~S}_3$ is not soluble in yellow ammonium sulphide.
Reason : The common ion effect due to $S^{2-}$ ions reduces the solubility of $\mathrm{Sb}_2 \mathrm{~S}_3$.
Options:
Reason : The common ion effect due to $S^{2-}$ ions reduces the solubility of $\mathrm{Sb}_2 \mathrm{~S}_3$.
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Verified Answer
The correct answer is:
If both assertion and reason are false.
$\mathrm{Sb}_2 \mathrm{~S}_3$ is soluble in yellow ammonium sulphide.
$$
\mathrm{Sb}_2 \mathrm{~S}_3+3\left(\mathrm{NH}_4\right)_2 \mathrm{~S} \rightarrow 2\left(\mathrm{NH}_4\right)_3 \mathrm{SbS}_3
$$
$$
\mathrm{Sb}_2 \mathrm{~S}_3+3\left(\mathrm{NH}_4\right)_2 \mathrm{~S} \rightarrow 2\left(\mathrm{NH}_4\right)_3 \mathrm{SbS}_3
$$
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