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Assertion : Two bodies of masses $M$ and $m$ $(M>m)$ are allowed to fall from the same height if the air resistance for each be the same then both the bodies will reach the earth simultaneously.
Reason : For same air resistance, acceleration of both the bodies will be same.
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Reason : For same air resistance, acceleration of both the bodies will be same.
Solution:
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Verified Answer
The correct answer is:
If both assertion and reason are false.
The force acting on the body of mass $M$ are its weight $M g$ acting vertically downwards $\therefore$ and air resistance $F$ acting vertically upward. $\therefore$ Acceleration of the body
$a=\frac{M g-F}{M}=g-\frac{F}{M}$
Now, $M>m$, therefore, the body with larger mass will have greater acceleration and it will reach the ground first.
$a=\frac{M g-F}{M}=g-\frac{F}{M}$
Now, $M>m$, therefore, the body with larger mass will have greater acceleration and it will reach the ground first.
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