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Assuming fully decomposed, the volume of $\mathrm{CO}_2$ released at STP on heating $9.85 \mathrm{~g}$ of $\mathrm{BaCO}_3$ (Atomic mass of $B a=137)$ will be
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$1.12 L$
\(\mathrm{BaCO}_3 \rightarrow \mathrm{BaO}+\mathrm{CO}_2 \uparrow\)
Molecular weight of \(\mathrm{BaCO}_3=137+12+3 \times 16=197\)
\(\therefore \quad 197 \mathrm{gm}\) produces 22.4 L at S.T.P.
\(\therefore \quad 9.85 \mathrm{gm}\) produces \(\frac{22.4}{197} \times 9.85=1.12 \mathrm{~L}\) at S.T.P.
Molecular weight of \(\mathrm{BaCO}_3=137+12+3 \times 16=197\)
\(\therefore \quad 197 \mathrm{gm}\) produces 22.4 L at S.T.P.
\(\therefore \quad 9.85 \mathrm{gm}\) produces \(\frac{22.4}{197} \times 9.85=1.12 \mathrm{~L}\) at S.T.P.
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