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Question: Answered & Verified by Expert
At a certain height, a body at rest explodes into two equal fragments with one fragment receiving a horizontal velocity of $10 \sqrt{3} \mathrm{~ms}^{-1}$. The horizontal distance between the two fragments, when their displacement vectors are inclined at $60^{\circ}$ relative to each other is $\left(\mathrm{g}=10 \mathrm{~ms}^{-2}\right)$
PhysicsMotion In Two DimensionsAP EAMCETAP EAMCET 2017 (24 Apr Shift 2)
Options:
  • A $40 \sqrt{3} \mathrm{~m}$
  • B $60 \sqrt{3} \mathrm{~m}$
  • C $240 \sqrt{3} \mathrm{~m}$
  • D $480 \sqrt{3} \mathrm{~m}$
Solution:
1016 Upvotes Verified Answer
The correct answer is: $60 \sqrt{3} \mathrm{~m}$
No solution. Refer to answer key.

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