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At $\mathrm{T}(\mathrm{K})$, the molar conductivity of $0.04 \mathrm{M}$ acetic acid is $7.8 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$. If the limiting molar conductivities of $\mathrm{H}^{+}$and $\mathrm{CH}_3 \mathrm{COO}^{-}$at $\mathrm{T}(\mathrm{K})$ are 349 and $41 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$ respectively, the dissociation constant of acetic acid is
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The correct answer is:
$1.63 \times 10^{-5}$
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