Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
At what temperature is the R.M.S. velocity of Hydrogen molecule equal to that of
an oxygen molecule at $47^{\circ} \mathrm{C}$ ?
(Molecular weight of hydrogen $=2$, Molecular weight of oxygen $=32$ )
PhysicsKinetic Theory of GasesMHT CETMHT CET 2020 (13 Oct Shift 1)
Options:
  • A $80 \mathrm{~K}$
  • B $20 \mathrm{~K}$
  • C $40 \mathrm{~K}$
  • D $60 \mathrm{~K}$
Solution:
2307 Upvotes Verified Answer
The correct answer is: $20 \mathrm{~K}$
The r.m.s. velocity of a molecule is given by
$$
\begin{aligned}
\mathrm{C} &=\sqrt{\frac{3 \mathrm{RT}}{\mathrm{M}}} \\
\therefore \frac{\mathrm{C}_{\mathrm{H}}}{\mathrm{C}_{\mathrm{o}}} &=\sqrt{\frac{\mathrm{T}_{\mathrm{H}}}{\mathrm{T}_{\mathrm{o}}} \cdot \frac{\mathrm{M}_{\mathrm{o}}}{\mathrm{M}_{\mathrm{H}}}} \\
\therefore \mathrm{C}_{\mathrm{H}} &=\mathrm{C}_{\mathrm{o}} \\
\frac{\mathrm{T}_{\mathrm{H}}}{\mathrm{T}_{\mathrm{o}}} \cdot & \frac{\mathrm{M}_{0}}{\mathrm{M}_{\mathrm{H}}}=1, \quad \mathrm{~T}_{\mathrm{H}}=47+273=320 \\
\therefore \mathrm{T}_{\mathrm{H}} &=\frac{\mathrm{M}_{\mathrm{H}}}{\mathrm{M}_{\mathrm{o}}} \cdot \mathrm{T}_{\mathrm{o}}=\frac{2}{32} \cdot 320=20 \mathrm{~K}
\end{aligned}
$$

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.