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Question: Answered & Verified by Expert
Atomic radius (pm) of $\mathrm{Al}, \mathrm{Si}, \mathrm{N}$ and $\mathrm{F}$ respectively is
ChemistryClassification of Elements and Periodicity in PropertiesTS EAMCETTS EAMCET 2017
Options:
  • A $117,143,64,74$
  • B $143,117,74,64$
  • C $143,47,64,74$
  • D $64,74,117,143$
Solution:
1105 Upvotes Verified Answer
The correct answer is: $143,117,74,64$
$\mathrm{Al}, \mathrm{Si}$ belory to $3 \mathrm{rd}$ period of periodic table while $\mathrm{N}_1$ and fluorine to second period.
The size of element decreases from left to right in a period hence the order of size is $\mathrm{Al}>\mathrm{Si}>\mathrm{N}>\mathrm{F}$

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