Search any question & find its solution
Question:
Answered & Verified by Expert
Atomic radius (pm) of $\mathrm{Al}, \mathrm{Si}, \mathrm{N}$ and $\mathrm{F}$ respectively is
Options:
Solution:
1105 Upvotes
Verified Answer
The correct answer is:
$143,117,74,64$
$\mathrm{Al}, \mathrm{Si}$ belory to $3 \mathrm{rd}$ period of periodic table while $\mathrm{N}_1$ and fluorine to second period.
The size of element decreases from left to right in a period hence the order of size is $\mathrm{Al}>\mathrm{Si}>\mathrm{N}>\mathrm{F}$
The size of element decreases from left to right in a period hence the order of size is $\mathrm{Al}>\mathrm{Si}>\mathrm{N}>\mathrm{F}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.