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$\mathrm{Be}$ and $\mathrm{Al}$ show similarities in properties due to diagonal relationship except in the property $X$ given below. What is $X$ ?
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Verified Answer
The correct answer is:
In vapour phase chlorides of both have $\mathrm{Cl}^{-}$bridged chloride structure
The oxides and hydroxides of both $\mathrm{Be}$ and $\mathrm{Al}$ are amphoteric and dissolve in sodium hydroxide solution as well as in hydrochloric acid.
$$
\begin{aligned}
& \mathrm{BeO}+2 \mathrm{HCl} \longrightarrow \mathrm{BeCl}_2+\mathrm{H}_2 \mathrm{O} \\
& \mathrm{BeO}+2 \mathrm{NaOH} \longrightarrow \mathrm{Na}_2 \mathrm{BeO}_2+\mathrm{H}_2 \mathrm{O} \\
& \mathrm{Al}_2 \mathrm{O}_3+6 \mathrm{HCl} \longrightarrow 2 \mathrm{AlCl}_3+3 \mathrm{H}_2 \mathrm{O} \\
& \mathrm{Al}_2 \mathrm{O}_3+2 \mathrm{NaOH} \longrightarrow 2 \mathrm{NaAlO}_2+\mathrm{H}_2 \mathrm{O}
\end{aligned}
$$
$$
\begin{aligned}
& \mathrm{BeO}+2 \mathrm{HCl} \longrightarrow \mathrm{BeCl}_2+\mathrm{H}_2 \mathrm{O} \\
& \mathrm{BeO}+2 \mathrm{NaOH} \longrightarrow \mathrm{Na}_2 \mathrm{BeO}_2+\mathrm{H}_2 \mathrm{O} \\
& \mathrm{Al}_2 \mathrm{O}_3+6 \mathrm{HCl} \longrightarrow 2 \mathrm{AlCl}_3+3 \mathrm{H}_2 \mathrm{O} \\
& \mathrm{Al}_2 \mathrm{O}_3+2 \mathrm{NaOH} \longrightarrow 2 \mathrm{NaAlO}_2+\mathrm{H}_2 \mathrm{O}
\end{aligned}
$$
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