Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
Block B starts from rest and accelerates as aB= 12t m s-2. Simultaneously another end of the string is pulled with constant acceleration a0. If at t=3 s, block A comes to rest then the value of a0 (in m s-2) is equal to

PhysicsLaws of MotionJEE Main
Solution:
2321 Upvotes Verified Answer
The correct answer is: 18
12t – 2aAa0 = 0
aA=6t-a02
0vdv=0t6t-a02 dt
v=3t2-a02t
⇒ v = 0, ⇒  3t=a02
⇒ a0 = 6t
 

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.