Bond angles of $ \mathrm{NH}_{3}, \mathrm{PH}_{3}, \mathrm{AsH}_{3} $ and $ \mathrm{SbH}_{3} $ are in the order

Question

Bond angles of $ \mathrm{NH}_{3}, \mathrm{PH}_{3}, \mathrm{AsH}_{3} $ and $ \mathrm{SbH}_{3} $ are in the order, $ \mathrm{PH}_{3}>\mathrm{AsH}_{3}>\mathrm{SbH}_{3}>\mathrm{NH}_{3} $, $ \mathrm{SbH}_{3}>\mathrm{AsH}_{3}>\mathrm{PH}_{3}>\mathrm{NH}_{3} $, $ \mathrm{SbH}_{3}>\mathrm{AsH}_{3}>\mathrm{NH}_{3}>\mathrm{PH}_{3} $, $ \mathrm{NH}_{3}>\mathrm{PH}_{3}>\mathrm{AsH}_{3}>\mathrm{SbH}_{3} $

MARKS App · Accepted Answer

According to Drago's rule, elements belonging to the third period or below do not show hybridisation. This is accompanied by a decrease in bond angle to nearly 90 ° . However, in the case of ammonia, the bond angle is approximately 107 ° . N H 3 > P H 3 > A s H 3 > S b H 3

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