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Question: Answered & Verified by Expert
$\mathrm{Br}^{-}$is converted into $\mathrm{Br}_2$ by using
Chemistryp Block Elements (Group 15, 16, 17 & 18)JEE Main
Options:
  • A $\mathrm{Cl}_2$
  • B Conc. $\mathrm{HCl}$
  • C $\mathrm{HBr}$
  • D $\mathrm{H}_2 \mathrm{~S}$
Solution:
2284 Upvotes Verified Answer
The correct answer is: $\mathrm{Cl}_2$
$\mathrm{Cl}_2+2 \mathrm{Br}^{-} \rightarrow 2 \mathrm{Cl}^{-}+\mathrm{Br}_2$

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