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By dissolving $0.35$ mole of sodium chloride in water, $1.30 \mathrm{~L}$ of salt solution is obtained. The molarity of the resulting solution should be reported as -
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$0.269$
$\text { Molarity }=\frac{\text { Moles of Solute }}{\text { Vol.of Solution }}=\frac{0.35}{1.3}=0.269$
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