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Calculate final volume of a gas when pressure of $60 \mathrm{~mL}$ gas is increased from 1 to $1.5 \mathrm{~atm}$, keeping temperature constant.
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Verified Answer
The correct answer is:
$4 \times 10^{-2} \mathrm{dm}^3$
$\mathrm{P}_1 \mathrm{~V}_1=\mathrm{P}_2 \mathrm{~V}_2$
$1 \times 60=1.5 \times V_2$
$\mathrm{V}_2=\frac{60}{1.5}=40 \mathrm{ml}$
or $4 \times 10^{-2} \mathrm{dm}^3$
$1 \times 60=1.5 \times V_2$
$\mathrm{V}_2=\frac{60}{1.5}=40 \mathrm{ml}$
or $4 \times 10^{-2} \mathrm{dm}^3$
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