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Calculate mass of a divalent metal produced at cathode by passing $5 \mathrm{amp}$ current through its salt solution for 100 minutes. (Molar mas of metal $=x$ )
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The correct answer is:
$\frac{30}{193} x$
$\begin{aligned} & \mathrm{W}=\frac{\mathrm{E}}{\mathrm{F}} \mathrm{It}=\frac{\mathrm{X}}{2 \times 96500} \times 5 \times 100 \times 60 \\ & =\frac{\mathrm{x} \times 5 \times 30}{965} \\ & \mathrm{~W}=\frac{30 \mathrm{x}}{193}\end{aligned}$
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