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Calculate the energy needed to convert three moles of sodium atoms in the gaseous state to sodium ions. The ionization energy of sodium is $495 \mathrm{~kJ} \mathrm{~mol}^{-1}-$
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$1485 \mathrm{~kJ}$
Energy needed to convert 1 mole of sodium $(\mathrm{g})$ to sodium ions $=495 \mathrm{~kJ}$
$\therefore$ Energy needed to convert 3 moles of $\mathrm{Na}(\mathrm{g})$ to $\mathrm{Na}^{+}$ions $=495 \times 3=1485 \mathrm{~kJ}$
$\therefore$ Energy needed to convert 3 moles of $\mathrm{Na}(\mathrm{g})$ to $\mathrm{Na}^{+}$ions $=495 \times 3=1485 \mathrm{~kJ}$
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