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Calculate the number of atoms in each of the following
(i) 52 moles of \(\mathbf{A r}\)
(ii) \(52 \mathrm{u}\) of \(\mathrm{He}\)
(iii) \(52 \mathrm{~g}\) of \(\mathrm{He}\).
(i) 52 moles of \(\mathbf{A r}\)
(ii) \(52 \mathrm{u}\) of \(\mathrm{He}\)
(iii) \(52 \mathrm{~g}\) of \(\mathrm{He}\).
Solution:
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(i) \(1 \mathrm{~mol}\) of \(\mathrm{Ar}=6.022 \times 10^{23}\) atoms
\(52 \mathrm{~mol}\) of \(\mathrm{Ar}=52 \times 6.022 \times 10^{23}\) atom \(=3.131 \times 10^{25}\) atoms
(ii) \(4 \mathrm{u}\) of \(\mathrm{He}=1\) atom of \(\mathrm{He}\)
\(52 \mathrm{u}\) of \(\mathrm{He}=\frac{1}{4} \times 52\) atoms \(=13\) atoms
(iii) 1 mole of \(\mathrm{He}=4 \mathrm{~g}\) of \(\mathrm{He}=6.022 \times 10^{23}\) atoms
\(52 \mathrm{~g}\) of \(\mathrm{He}=\frac{6.022 \times 10^{23}}{4} \times 52\) atoms \(=7.8286 \times 10^{24}\) atoms
\(52 \mathrm{~mol}\) of \(\mathrm{Ar}=52 \times 6.022 \times 10^{23}\) atom \(=3.131 \times 10^{25}\) atoms
(ii) \(4 \mathrm{u}\) of \(\mathrm{He}=1\) atom of \(\mathrm{He}\)
\(52 \mathrm{u}\) of \(\mathrm{He}=\frac{1}{4} \times 52\) atoms \(=13\) atoms
(iii) 1 mole of \(\mathrm{He}=4 \mathrm{~g}\) of \(\mathrm{He}=6.022 \times 10^{23}\) atoms
\(52 \mathrm{~g}\) of \(\mathrm{He}=\frac{6.022 \times 10^{23}}{4} \times 52\) atoms \(=7.8286 \times 10^{24}\) atoms
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