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Calculate the number of protons, neutrons and electrons in \({ }_{16}^{32} \mathrm{~S}^{2-}\).
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Verified Answer
The correct answer is:
\(16,16,18\)
An element can be represented as \({ }_Z^A X\). where, \(X=\) symbol of element
\(Z=\) atomic number or number of protons
\(A=\) mass number \(=\) sum of number of protons and neutrons
Therefore, for \({ }_{16}^{32} \mathrm{~S}^{-2}\), number of protons \(=16\), number of neturons \(=32-16=16\) and electrons \(=18\)
Hence, the correct option is (d).
\(Z=\) atomic number or number of protons
\(A=\) mass number \(=\) sum of number of protons and neutrons
Therefore, for \({ }_{16}^{32} \mathrm{~S}^{-2}\), number of protons \(=16\), number of neturons \(=32-16=16\) and electrons \(=18\)
Hence, the correct option is (d).
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