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Calculate the radius of first orbit of $\mathrm{Be}^{3+}$.
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Verified Answer
The correct answer is:
$13.23 \mathrm{pm}$
$\begin{aligned} r_n & =\frac{n^2}{z} \times 0.53 \AA \\ & =\frac{1}{4} \times 0.53 \AA \\ & =\frac{1}{4} \times 0.53 \AA \\ & =0.1325 \AA \\ & =13.25 \mathrm{pm}\end{aligned}$
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