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Calculate the radius of metal atom in bcc unit cell having edge length $287 \mathrm{pm}$.
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Verified Answer
The correct answer is:
$124.27 \mathrm{pm}$
For bcc unit cell, $4 \mathrm{r}=\sqrt{3} \mathrm{a}$
$$
\therefore \quad \mathrm{r}=\frac{\sqrt{3}}{4} \mathrm{a}=\frac{1.732 \times 287}{4}=124.27 \mathrm{pm}
$$
$$
\therefore \quad \mathrm{r}=\frac{\sqrt{3}}{4} \mathrm{a}=\frac{1.732 \times 287}{4}=124.27 \mathrm{pm}
$$
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