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Question: Answered & Verified by Expert
Calculate the time interval between 33% decay and 67% decay if half-life of a substance is 20 min.
PhysicsNuclear PhysicsJEE MainJEE Main 2021 (16 Mar Shift 2)
Options:
  • A 60 min
  • B 20 min
  • C 40 min
  • D 13 min
Solution:
2092 Upvotes Verified Answer
The correct answer is: 20 min

N1=N0e-λt1

N1 N0=e-λt1

0.67=e-λt1

ln0.67=-λt1

 N2=N0e-λt2

N2 N0=e-λt2

0.33=e-λt2

ln0.33=-λt2

ln0.67-ln0.33=λt1-λt2

λt1-t2=ln0.670.33

λt1-t2ln2

t1-t2ln2λ=t1/2

Half life =t1/2=20 minutes.

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