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Calculate the total pressure in a mixture of \(8 \mathrm{~g}\) of dioxygen and \(4 \mathrm{~g}\) of dihydrogen confined in a vessel of \(1 \mathrm{dm}^3\) at \(27^{\circ} \mathrm{C} . \mathrm{R}=\mathbf{0 . 0 8 3}\) bar \(^2 \mathrm{dm}^3 \mathrm{~K}^{-1} \mathrm{~mol}^{-1}\).
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Molar mass of \(\mathrm{O}_2=32 \mathrm{~g} \mathrm{~mol}^{-1}\)
\(\therefore \quad 8 \mathrm{~g}^2\) of \(\mathrm{O}_2=8 / 32 \mathrm{~g} \mathrm{~mol}^{-1}=0.25 \mathrm{~mol}\)
Molar mass of \(\mathrm{H}_2=2 \mathrm{~g} \mathrm{~mol}^{-1}\)
\(\therefore \quad 4 \mathrm{~g}\) of \(\mathrm{H}_2=4 / 2 \mathrm{~g} \mathrm{~mol}^{-1}=2 \mathrm{~mol}\)
\(\therefore\) Total number of moles (n)
\(=2 \mathrm{~mol}+0.25 \mathrm{~mol}=2.25 \mathrm{~mol}\)
\(\mathrm{V}=1 \mathrm{dm}^3, \mathrm{~T}=27^{\circ} \mathrm{C}\)
\(=300 \mathrm{~K}, \mathrm{R}=0.083 \mathrm{bar} \mathrm{dm}^3 \mathrm{~K}^{-1} \mathrm{~mol}^{-1}\)
\(\mathrm{PV}=\mathrm{n}\) RT or, \(\mathrm{P}=\frac{\mathrm{nRT}}{\mathrm{V}}\)
\(=56.025 \mathrm{bar}\)
\(\therefore \quad 8 \mathrm{~g}^2\) of \(\mathrm{O}_2=8 / 32 \mathrm{~g} \mathrm{~mol}^{-1}=0.25 \mathrm{~mol}\)
Molar mass of \(\mathrm{H}_2=2 \mathrm{~g} \mathrm{~mol}^{-1}\)
\(\therefore \quad 4 \mathrm{~g}\) of \(\mathrm{H}_2=4 / 2 \mathrm{~g} \mathrm{~mol}^{-1}=2 \mathrm{~mol}\)
\(\therefore\) Total number of moles (n)
\(=2 \mathrm{~mol}+0.25 \mathrm{~mol}=2.25 \mathrm{~mol}\)
\(\mathrm{V}=1 \mathrm{dm}^3, \mathrm{~T}=27^{\circ} \mathrm{C}\)
\(=300 \mathrm{~K}, \mathrm{R}=0.083 \mathrm{bar} \mathrm{dm}^3 \mathrm{~K}^{-1} \mathrm{~mol}^{-1}\)
\(\mathrm{PV}=\mathrm{n}\) RT or, \(\mathrm{P}=\frac{\mathrm{nRT}}{\mathrm{V}}\)
\(=56.025 \mathrm{bar}\)
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