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Calculate the wavelength of an electron moving with a velocity of \(2.05 \times 10^7 \mathrm{~ms}^{-1}\).
Solution:
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Verified Answer
By de Broglie equation
\(\begin{aligned}
&\lambda=\frac{h}{\mathrm{mv}}=\frac{6.626 \times 10^{-34} \mathrm{Js}}{\left(9.11 \times 10^{-31} \mathrm{~kg}\right)\left(2.05 \times 10^7 \mathrm{~ms}^{-1}\right)} \\
&=3.55 \times 10^{-11} \mathrm{~m} \quad\left(1 \mathrm{~J}=1 \mathrm{~kg} \mathrm{~m}^2 \mathrm{~s}^{-2}\right)
\end{aligned}\)
\(\begin{aligned}
&\lambda=\frac{h}{\mathrm{mv}}=\frac{6.626 \times 10^{-34} \mathrm{Js}}{\left(9.11 \times 10^{-31} \mathrm{~kg}\right)\left(2.05 \times 10^7 \mathrm{~ms}^{-1}\right)} \\
&=3.55 \times 10^{-11} \mathrm{~m} \quad\left(1 \mathrm{~J}=1 \mathrm{~kg} \mathrm{~m}^2 \mathrm{~s}^{-2}\right)
\end{aligned}\)
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