Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
Calculate the wavelength of light required to break the bond between two chlorine atoms in a chlorine molecule. The Cl – Cl bond energy is 243 kJ mol-1(h=6.6×10-34Js;c=3×108m/s ; Avogadro’s number =6.02×1023mol-1 )
ChemistryStructure of AtomNEET
Options:
  • A 8.18×10-31 m
  • B 6.26×10-21 m
  • C 4.905×10-m
  • D 4.1×10-6m
Solution:
2899 Upvotes Verified Answer
The correct answer is: 4.905×10-m
Energy required to break one Cl − Cl bond =bonenergpemoleAvogadronumber=243×1036.02×1023  J
Let the wavelength of the photon to cause rupture of one Cl – Cl bond be λ,
λ=hcE=6.6×10-34×3×108×6.02×1023243×103=119.196243×10-34×1031×10-3=4.905×10-m.

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.