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Question: Answered & Verified by Expert
$\mathrm{CH}_2=\mathrm{CH}_2+\mathrm{B}_2 \mathrm{H}_6 \xrightarrow[\mathrm{H}_2 \mathrm{SO}_4]{\mathrm{NaOH}}$ Product.
Product in above reaction is
ChemistryAlcohols Phenols and EthersJEE Main
Options:
  • A $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CHO}$
  • B $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{OH}$
  • C $\mathrm{CH}_3 \mathrm{CHO}$
  • D None of these
Solution:
1728 Upvotes Verified Answer
The correct answer is: $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{OH}$
$\mathrm{CH}_2=\mathrm{CH}_2+\mathrm{B}_2 \mathrm{H}_6 \xrightarrow[\mathrm{H}_2 \mathrm{SO}_4]{\mathrm{NaOH}} \mathrm{HC}_2 \mathrm{CH}_2 \mathrm{OH}$

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