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Question: Answered & Verified by Expert
$\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{C} \equiv \mathrm{CH} \xrightarrow{R}$ butanone $-2 . R$ is
ChemistryAldehydes and KetonesJIPMERJIPMER 2005
Options:
  • A $\mathrm{Hg}^{++} /$dil $\cdot \mathrm{H}_2 \mathrm{SO}_4$
  • B $\mathrm{KMnO}_4$
  • C $\mathrm{KClO}_3$
  • D $\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7$
Solution:
2954 Upvotes Verified Answer
The correct answer is: $\mathrm{Hg}^{++} /$dil $\cdot \mathrm{H}_2 \mathrm{SO}_4$
Alkyne change to ketone upon hydrolysis in presence of mercury salt.
$\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{C} \equiv \mathrm{CH} \xrightarrow[\mathrm{Hg}^{2+} / \mathrm{H}_2 \mathrm{SO}_4]{\mathrm{H} . \mathrm{OH}}$

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