Search any question & find its solution
Question:
Answered & Verified by Expert
$\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{C} \equiv \mathrm{CH} \xrightarrow{R}$ butanone $-2 . R$ is
Options:
Solution:
2954 Upvotes
Verified Answer
The correct answer is:
$\mathrm{Hg}^{++} /$dil $\cdot \mathrm{H}_2 \mathrm{SO}_4$
Alkyne change to ketone upon hydrolysis in presence of mercury salt.
$\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{C} \equiv \mathrm{CH} \xrightarrow[\mathrm{Hg}^{2+} / \mathrm{H}_2 \mathrm{SO}_4]{\mathrm{H} . \mathrm{OH}}$
$\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{C} \equiv \mathrm{CH} \xrightarrow[\mathrm{Hg}^{2+} / \mathrm{H}_2 \mathrm{SO}_4]{\mathrm{H} . \mathrm{OH}}$

Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.