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$\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{OH} \stackrel{\mathrm{A}}{\longrightarrow}$
$\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{Cl} \stackrel{B}{\longrightarrow} \mathrm{CH}_{2}=\mathrm{CH}_{2} \cdot A$ and $B$ in this sequence of reactions are
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$\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{Cl} \stackrel{B}{\longrightarrow} \mathrm{CH}_{2}=\mathrm{CH}_{2} \cdot A$ and $B$ in this sequence of reactions are
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Verified Answer
The correct answer is:
$\mathrm{PCl}_{5}$ and $\mathrm{KOH}($ alc $)$
The reaction is as follows,
$\therefore \quad A=\mathrm{PCl}_{5}$ and $B=$ alc. $\mathrm{KOH}$.
$\therefore \quad A=\mathrm{PCl}_{5}$ and $B=$ alc. $\mathrm{KOH}$.
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