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$\mathrm{CH}_3 \mathrm{COOH} \xrightarrow{\mathrm{PBr}_2} \mathrm{CH}_2 \mathrm{BrCOOH}$
This reaction is called
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This reaction is called
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The correct answer is:
Hell-Volhard-Zelinsky reaction
The substitution of $\alpha$-hydrogen atom by halogens in acids, is called Hell-VolhardZelinsky (HVZ) reaction
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