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Charges $+q$ and $-q$ are placed at points $\mathrm{A}$ and $\mathrm{B}$ respectively which are a distance $2 L$ apart, $\mathrm{C}$ is the midpoint between $\mathrm{A}$ and $\mathrm{B}$. The work done in moving a charge $+\mathrm{Q}$ along the semicircle CRD is
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The correct answer is:
$\frac{q Q}{3 \pi \varepsilon_0 L}$
$W=\Delta U=\mathrm{Q}\left(V_D-V_C\right)$
where $V_c=0$
$=Q\left[\frac{q}{4 \pi \varepsilon_0(3 L)}-\frac{q}{4 \pi \varepsilon_0(L)} .0\right]$
$\frac{q Q}{3 \pi \varepsilon_0 L}$
where $V_c=0$
$=Q\left[\frac{q}{4 \pi \varepsilon_0(3 L)}-\frac{q}{4 \pi \varepsilon_0(L)} .0\right]$
$\frac{q Q}{3 \pi \varepsilon_0 L}$
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