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Question: Answered & Verified by Expert
Children have been invited to a birthday party. It is necessary to give them return gifts. For the purpose, it was decided that they would be given pens and pencils in a bag. It was also decided that the number of items in a bag would be atleast 5 . If the cost of a pen is \(₹ 10\) and cost of a pencil is ₹5, minimize the cost of a bag containing pens and pencils. Formulation of LPP for this problem is
MathematicsPermutation CombinationVITEEEVITEEE 2022
Options:
  • A Minimize \(\mathrm{C}=5 \mathrm{x}+10 \mathrm{y}\) subject to \(\mathrm{x}+\mathrm{y} \leq 10\), \(x \geq 0, y \geq 0\)
  • B Minimize \(C=5 x+10 y\) subject to \(x+y \geq 10\), \(\mathrm{x} \geq 0, \mathrm{y} \geq 0\)
  • C Minimize \(\mathrm{C}=5 \mathrm{x}+10 \mathrm{y}\) subject to \(\mathrm{x}+\mathrm{y} \geq 5\), \(x \geq 0, y \geq 0\)
  • D Minimize \(\mathrm{C}=5 \mathrm{x}+10 \mathrm{y}\) subject to \(\mathrm{x}+\mathrm{y} \leq 5\), \(x \geq 0, y \geq 0\)
Solution:
1588 Upvotes Verified Answer
The correct answer is: Minimize \(\mathrm{C}=5 \mathrm{x}+10 \mathrm{y}\) subject to \(\mathrm{x}+\mathrm{y} \geq 5\), \(x \geq 0, y \geq 0\)
Let the no. of pencils in a bag be \(x\)
Let the no. of pens in a bag be \(y\). There should be at least 5 items in a bag
\(\therefore\) we have \(\mathrm{x}+\mathrm{y} \geq 5\)
cost of pencils in a bag \(=₹ 5 \mathrm{x}\)
cost of pens in bag \(₹ 10 \mathrm{y}\)
\(\therefore\) Total cost of a bag \(=5 \mathrm{x}+10 \mathrm{y}\),
The total cost has to minimized
\(\therefore\) Objective function is minimize \(C=5 x+10 y\) subject to \(x+y \geq 5, x \geq 0, y \geq 0\)

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