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Choose the correct relation between polarisation 'P' and electric susceptibility $^{4} \chi_{e}{ }^{\prime}$ of dielectric material. $(\mathrm{E}=$ electric field $)$

PhysicsElectrostaticsMHT CETMHT CET 2020 (20 Oct Shift 2)

Options:

A $\mathrm{P}=\frac{\chi_{\mathrm{e}}}{\mathrm{E}^{2}}$
B $\mathrm{P}=\frac{\chi_{\mathrm{e}}}{\mathrm{E}}$
C $\mathrm{P}=\chi_{\mathrm{e}} \mathrm{E}$
D $\mathrm{P}=\chi_{\mathrm{e}}^{2} \mathrm{E}$

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