Circle x 2 + y 2 + 6 y = 0 touches, y -axis at the origin, x -axis at the origin, x -axis at the point ( 3 , 0 ), The line y + 3 = 0

Centre is ( 0 , − 3 ) and R = 0 2 + 9 + 0 = 3

Circle x 2 + y 2 + 6 y = 0 touches

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Circle $x^2+y^2+6 y=0$ touches

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1230 Upvotes Verified Answer

The correct answer is: $x$-axis at the origin

Centre is $(0,-3)$ and $R=\sqrt{0^2+9+0}=3$

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